**The formula to use for copper conductors is:**

S = 0.017 x L x I / PT

S = section of the copper conductor expressed in square millimeters

L = driver's outward + return length expressed in meters

I = the intensity expressed in Amperes

PT = voltage loss accepted on the cables expressed in

Volts

Manual** Calculation of the length:**

Whatever the nature of the hull, there must always be a "go" or positive conductor in

general red and a black "return" or negative conductor.

As specified in Division 240, the shell material should never be used in

as a driver.

Intensity:

The nominal current is sometimes provided: in this case, nothing could be simpler.

Often only the power of the device is indicated. In this case, it is necessary to calculate

the intensity using the following formula:

P = U x I or I = P / U

P = Power expressed in Watts

U = nominal voltage of the installation (12 V, 24 V or 48 V) expressed in Volts

I = Intensity expressed in Amps

PT or loss of voltage in the cables:

A current flowing through the cables generates a voltage (Ohm's law).

Division 240 specifies that this must remain less than 5% of the nominal voltage of

the installation is:

Maximum PT allowed in 12 V = 0.6 V (5% of 12 V)

24 V = 1.2 V (5% of 24 V)

Reasonable PT a priori in 12 V = 0.3 V (2.5% of 12 V)

24 V = 0.6 V (2.5% of 12 V)** 2. Example:**

Installation of a 110 W 12 V pump

**Distance between the fuse or circuit breaker and the pump via the complete routing: **

meters. Round trip + return = 14 m.

The nominal current is: 110/12 = 9.2 A

The strictly minimum section of the conductor must be:

0.017 x 14 x 9.2 / 0.6 = 3.6 mm²

**The so-called "reasonable" section is:**

0.017 x 10 x 9.2 / 0.3 = 7.3 mm²

A section of 4² is sufficient "legally" but a conductor of 6 is preferable.

As far as I'm concerned, I prefer to send the maximum voltage on the pumps and I

will carry out the installation in 10²

**The formula to use for copper conductors is:**

S = 0.017 x L x I / PT

S = section of the copper conductor expressed in square millimeters

L = driver's outward + return length expressed in meters

I = the intensity expressed in Amperes

PT = voltage loss accepted on the cables expressed in

Volts

Manual** Calculation of the length:**

Whatever the nature of the hull, there must always be a "go" or positive conductor in

general red and a black "return" or negative conductor.

As specified in Division 240, the shell material should never be used in

as a driver.

Intensity:

The nominal current is sometimes provided: in this case, nothing could be simpler.

Often only the power of the device is indicated. In this case, it is necessary to calculate

the intensity using the following formula:

P = U x I or I = P / U

P = Power expressed in Watts

U = nominal voltage of the installation (12 V, 24 V or 48 V) expressed in Volts

I = Intensity expressed in Amps

PT or loss of voltage in the cables:

A current flowing through the cables generates a voltage (Ohm's law).

Division 240 specifies that this must remain less than 5% of the nominal voltage of

the installation is:

Maximum PT allowed in 12 V = 0.6 V (5% of 12 V)

24 V = 1.2 V (5% of 24 V)

Reasonable PT a priori in 12 V = 0.3 V (2.5% of 12 V)

24 V = 0.6 V (2.5% of 12 V)** 2. Example:**

Installation of a 110 W 12 V pump

**Distance between the fuse or circuit breaker and the pump via the complete routing: **

meters. Round trip + return = 14 m.

The nominal current is: 110/12 = 9.2 A

The strictly minimum section of the conductor must be:

0.017 x 14 x 9.2 / 0.6 = 3.6 mm²

**The so-called "reasonable" section is:**

0.017 x 10 x 9.2 / 0.3 = 7.3 mm²

A section of 4² is sufficient "legally" but a conductor of 6 is preferable.

As far as I'm concerned, I prefer to send the maximum voltage on the pumps and I

will carry out the installation in 10²

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