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Sunday, May 21, 2023

the principles of differential protection


 Although nowadays differential protection is achieved numerically, in order to understand the principles of differential protection it is useful to analyze the ubiquitous electromechanical relay. Figure 1 shows a simple differential protection scheme, also known as a Merz-Price scheme.


In this simple scheme, we can assume that under normal operating conditions, the current entering into the piece of equipment under protection  to its exiting current. In this example, we will assume that the entry and exit currents are equal.


A circuit breaker on either side of the equipment under protection is controlled by an overcurrent relay.

Current transformers of identical types and  are installed on either side of the equipment. These current transformers induce identical secondary currents because their primary currents are identical and they have the same turns ratio.



Consider a fault . A large current would flow through the fault, thus the current exiting the equipment would rapidly reduce resulting in a reduced secondary current in . This would cause a current to flow through the relay, which would be of a magnitude sufficient to trip the circuit breakers.

You can see that in this case, the current exiting the equipment, albeit large, is still the same as the current entering it, therefore the relay will not trip. , because faults external to the equipment are in a different  and are protected within another scheme.


If the equipment to be protected is a busbar, or generator winding, for instance, it is clear that the exit current is the same as the entry current. If, however, the equipment is a transformer where the turns ratio is not equal to one, the current entering will be different from the current exiting.


In this case, the current transformers must be balanced with an equivalent turns ratio differential.


, the current in the current transformers do not directly control the operating coil which trips the circuit breakers, so the connectivity is not as it is shown in this example. In reality, the currents from the current transformers are simply input to the IED, where they are sampled and digitized.



 Although nowadays differential protection is achieved numerically, in order to understand the principles of differential protection it is useful to analyze the ubiquitous electromechanical relay. Figure 1 shows a simple differential protection scheme, also known as a Merz-Price scheme.


In this simple scheme, we can assume that under normal operating conditions, the current entering into the piece of equipment under protection  to its exiting current. In this example, we will assume that the entry and exit currents are equal.


A circuit breaker on either side of the equipment under protection is controlled by an overcurrent relay.

Current transformers of identical types and  are installed on either side of the equipment. These current transformers induce identical secondary currents because their primary currents are identical and they have the same turns ratio.



Consider a fault . A large current would flow through the fault, thus the current exiting the equipment would rapidly reduce resulting in a reduced secondary current in . This would cause a current to flow through the relay, which would be of a magnitude sufficient to trip the circuit breakers.

You can see that in this case, the current exiting the equipment, albeit large, is still the same as the current entering it, therefore the relay will not trip. , because faults external to the equipment are in a different  and are protected within another scheme.


If the equipment to be protected is a busbar, or generator winding, for instance, it is clear that the exit current is the same as the entry current. If, however, the equipment is a transformer where the turns ratio is not equal to one, the current entering will be different from the current exiting.


In this case, the current transformers must be balanced with an equivalent turns ratio differential.


, the current in the current transformers do not directly control the operating coil which trips the circuit breakers, so the connectivity is not as it is shown in this example. In reality, the currents from the current transformers are simply input to the IED, where they are sampled and digitized.


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